Contents:
- A MAN HAS ED A MATHEMATIL FORMULA TO PROVE EVERYONE IS GAY — SORT OF
- CREATIVE MATHSUBSCRIBESIGN {"@NTEXT":","@TYPE":"NEWSARTICLE","URL":","MAENTYOFPAGE":","HEADLE":"MATH IS GAY","SCRIPTN":"HOW TEGORY THEORY IS QUEERG MATHEMATICS","IMAGE":[{"@TYPE":"IMAGEOBJECT","URL":"}],"DATEPUBLISHED":"2022-06-30T22:55:26+00:00","DATEMODIFIED":"2022-06-30T22:55:26+00:00","ISACCSIBLEFORFREE":TE,"THOR":[{"@TYPE":"PERSON","NAME":"NATHAN ONG","URL":","SCRIPTN":"ELEMENTAL MATHEMAGICIAN \UD83D\UDD25\UD83E\UDEA8\UD83D\UDCA7\UD83C\UDF43\UD83E\UDE84","INTIFIER":"ER:88373442","SAMEAS":["],"IMAGE":{"@TYPE":"IMAGEOBJECT","NTENTURL":","THUMBNAILURL":"}}],"PUBLISHER":{"@TYPE":"ORGANIZATN","NAME":"CREATIVE MATH","URL":","SCRIPTN":"IF APPLIED MATH IS REAL WRG, PURE MATH IS POETRY.\N\NLET'S GET ABSTRACT--LET'S GET CREATIVE \UD83D\UDCA1","TERACTNSTATISTIC":{"@TYPE":"INTERACTNCOUNTER","NAME":"SUBSCRIBERS","TERACTNTYPE":","ERINTERACTNCOUNT":1},"INTIFIER":"PUB:868430","LOGO":{"@TYPE":"IMAGEOBJECT","URL":","NTENTURL":","THUMBNAILURL":"},"IMAGE":{"@TYPE":"IMAGEOBJECT","URL":","NTENTURL":","THUMBNAILURL":"},"SAMEAS":["]}}SHARE THIS POSTMATH IS COPY LKFACEBOOKEMAILNOTOTHERMATH IS GAY
A MAN HAS ED A MATHEMATIL FORMULA TO PROVE EVERYONE IS GAY — SORT OF
Everyone’s gay, acrdg to this equatn (Pexels). A post on Redd which maths to ‘prove’ that straight partners are gay has gone viral. Reddors certaly seem to agree, wh the post om Alexanr — whose ername is makorrga — attractg around 19, 500 upvot sce was submted to the SudnlyGay subredd.
If you have two men a relatnship, you have one gay uple. Therefore, a member of that relatnship is half a gay uple. A happy gay uple (Amir Levy/Getty).
Alexanr explas that, if we hold the prev sums to be te, “1 woman + 1 man = 1/2 gay + 1/2 gay = gay.
CREATIVE MATHSUBSCRIBESIGN {"@NTEXT":","@TYPE":"NEWSARTICLE","URL":","MAENTYOFPAGE":","HEADLE":"MATH IS GAY","SCRIPTN":"HOW TEGORY THEORY IS QUEERG MATHEMATICS","IMAGE":[{"@TYPE":"IMAGEOBJECT","URL":"}],"DATEPUBLISHED":"2022-06-30T22:55:26+00:00","DATEMODIFIED":"2022-06-30T22:55:26+00:00","ISACCSIBLEFORFREE":TE,"THOR":[{"@TYPE":"PERSON","NAME":"NATHAN ONG","URL":","SCRIPTN":"ELEMENTAL MATHEMAGICIAN \UD83D\UDD25\UD83E\UDEA8\UD83D\UDCA7\UD83C\UDF43\UD83E\UDE84","INTIFIER":"ER:88373442","SAMEAS":["],"IMAGE":{"@TYPE":"IMAGEOBJECT","NTENTURL":","THUMBNAILURL":"}}],"PUBLISHER":{"@TYPE":"ORGANIZATN","NAME":"CREATIVE MATH","URL":","SCRIPTN":"IF APPLIED MATH IS REAL WRG, PURE MATH IS POETRY.\N\NLET'S GET ABSTRACT--LET'S GET CREATIVE \UD83D\UDCA1","TERACTNSTATISTIC":{"@TYPE":"INTERACTNCOUNTER","NAME":"SUBSCRIBERS","TERACTNTYPE":","ERINTERACTNCOUNT":1},"INTIFIER":"PUB:868430","LOGO":{"@TYPE":"IMAGEOBJECT","URL":","NTENTURL":","THUMBNAILURL":"},"IMAGE":{"@TYPE":"IMAGEOBJECT","URL":","NTENTURL":","THUMBNAILURL":"},"SAMEAS":["]}}SHARE THIS POSTMATH IS COPY LKFACEBOOKEMAILNOTOTHERMATH IS GAY
Therefore, he argu that “straight upl are gay. Straight upl are gay, acrdg to Alexanr (Pexels). 2 men= gay.
)Y homoCategory theory origally veloped as a tool to e problems, but as grew as a field, enabled mathematicians to bridge realms prevly thought to be theory abstracts llectns of objects (lled elements), topology abstracts space, rgs abstract arhmetic, and so on. The creative pot here is that the abstract ncept of a group is vered by the ncept of the homotopy class of a closed curve X, which pris an “elastic llectn” of curv.
It would seem that algebraic abstractn is opposed to the unprecise object of a homotopy class of curv. We want to show now that this mil terpretatn also holds for general theorem we n prove is a weaker statement than adjotns, namely a natural transformatn$$ Mu2Ma: HTop(H, F(G))\rightarrow Grp(\pi _1(H), G) $$wh a functor \(F:Grp\rightarrow HTop\) om the tegory Grp of groups to the tegory HTop of homotopy class of pathwise nnected topologil spac. More precisely, the nonil ntuo map \(F_G:Weg(G)\rightarrow F(G)\), when given the fundamental group evaluatn \(\pi _1(F_G)\), yields a group homomorphism diagram$$ Ker(\pi _1(F_G)) \rightarrowtail \pi _1(Wedge(G))\overset{\pi _1(F_G)}{\twoheadrightarrow}\pi _1(F(G)) $$whose kernel is Ker(p), the normal subgroup of \(\pi _1(Wedge(G))\overset{\sim}{\rightarrow}Free(G)\) fed above.